factoring: x2 - 3x - 28 = 0
@Kidkush24 help
can you find 2 numbers whose sum is -3 and product is -28 ?
7 and 4
one of them is negative, which ?
-7 and 4
correct! so, split up -3x as -7x+4x x^2 -7x+4x-28 now factor out x from first 2 terms and 4 from last two, can you ?
ummmm idthink so
ok, to factor out x from x^2-7x, we get x (x-7) and 4 from 4x-28. we get +4(x-7) so, x(x-7)+4(x-7) factor out (x-7) from this!
-7 4(x-7)??????
if you take (x-7) out from those 2 terms, what remains is (x-7) (x+4) thats it! factored.....
and don't forget the = 0 (x-7)(x+4) = 0 do you need to solve it too ? or just factoring ?
just factor can u help me with a few more
did you get this one properly ?
yes
yeah, then i can help u with next problems...just post them in a new post...so that if i am busy, others can help you too!
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