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MIT 18.06 Linear Algebra, Spring 2010
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OpenStudy (anonymous):
Pretty certain that solution to question 1.c on final is wrong. If a vector u is in the nullspace of A then Au=0. However, [1,2,0,1;2,4,1,4;3,6,3,9]*[3;-2;0;1] = [0;2;6] =/= 0. Correct answer should be [-2;1;0;0],[-1;0;-2;1]
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