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Find a cubic function with the given zeros. -2, 5, -6
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f(x) = x3 + 3x2 + 28x - 60 f(x) = x3 - 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x + 60
(x+2)(x-5)(x+6) Expand that.
how?
Multiply out; or FOIL.
ok
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Im stuck
Stuck where?
I dont know how to foil three sets of numbers
Do two first. Then do the third one.
so do (x+2)(x-5) and then (x-5)(x+6)
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No. Do (x+2)(x-5). For whatever you get; do that with (x+6)
ohhhhhhhhhhhhhh thats soooo easy
Let me see what you do.
\[(x+2)\text{ }(x-5 )( x+6)=\left(x^2-3 x-10\right)( x+6) \]
thats what I just got
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Go on from there. Just do the two as you would.
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