Question

There are two factors of -36 such that one factor is 11 less than half of the other factor. Choose all the pairs of these factors.

-2 and 18
-6 and 6
3 and -12
4 and -9

Answer 1

well, we know that the set is (a , b), and that say "a" is 11 less than half of "b"
or
\(a = \cfrac{b}{2}-11\)

Answer 2

so, try out the sets, plug the values for "b", see if you get a matching "a"

Answer 3

let's try the 1st one
-2 and 18

if b = 18, then a = -2

let's see
\(\large a = \frac{18}{2}-11\)
what do you get for "a"?

Answer 4

or solve
b^2/2 - 11b = -36

for b

a * b= -36
and a= b/2 -11

Answer 5

-2

Answer 6

is that correct?

Answer 7

yes

Answer 8

so y = 18, gave x = -2
so, that's the correct set :)