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Mathematics 20 Online
OpenStudy (anonymous):

(6c-10)(6c+10) solve this in special product

OpenStudy (anonymous):

What do you think it is?

OpenStudy (anonymous):

can you help me what is the solution of this

OpenStudy (anonymous):

\( 36c^2 - 100 \)

OpenStudy (anonymous):

I used \( a^2 - b^2 \) special formula to solve

OpenStudy (anonymous):

pls shown you solution

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

6c * 6c = 36c 10 * -10 = -100

OpenStudy (anonymous):

Also to check the solution http://www.wolframalpha.com/input/?i=%286c-10%29%286c%2B10%29+

OpenStudy (anonymous):

Really in the formula \( a^2 - b^2 \) you just take the first number and variable from (6c -10) and the second number and square them and plug it into the formule \( a^2 - b^2 \) so \( 6c^2 - 10^2 \) = \( 36c^2 - 100 \) We know to use this because both factors (6c - 10)(6c + 10) have the same numbers but different operators + -

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