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Mathematics 7 Online
OpenStudy (anonymous):

(1+〖tan〗^2 θ)/(1+〖cot〗^2 θ)=((1-tan⁡A)/(1-Cot A))^2

OpenStudy (anonymous):

(1+〖tan〗^2 A)/(1+〖cot〗^2 A)=((1-tan⁡A)/(1-Cot A))^2

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