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Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. y=x, y=(sqrt)x; about x=2
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you have found the volume about x=1. the part from 1 to 2 is to be integrated
But if it's rotated about the x=2 then that's all empty space?
I didn't draw the solid b/c the 3d part is difficult to draw but I thought it would look like a bowl with no bottom
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