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if log2(x)=log2(a)+log2(b)-log2(c) then what is x?
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log2(x)=log2(a)+log2(b)-log2(c) log2(x)=log2 [(a*b)/c] so x = (a * b / c)
the upstairs have made a perfect solution
lol..
it's chinglish really, in CHInese forum we oftener use the word 楼上,which means "upstairs" to refer to people who appeared before you
\[\large\boxed{\log_b p+\log_bq=\log_bpq}\\\large\boxed{\log_b p-\log_bq=\log_b\frac pq}\]
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