Question

What is common to the variation in the range and the height of a projectile?

a - horizontal velocity
b- time of flight vertical velocity, horizontal acceleration

c - vertical velocity

d - horizontal acceleration

Answer 1

Range = ucosA.t where A = angle of projection. Height = u^2 (sinA)^2 /2g. So R and H will vary due to variations in A basically because t is not common to both, but A is common to both. So ans is most probably A, C.

Answer 2

And there's no horizontal acceleration.

Answer 3

range=ucosA.*t=ucosA*2usinA/g [t=2usinA/g]
so vertical velocity is common to both