Given the triangle and equation below, what is the value of x? sec∠C - cot∠A = 3x
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sec∠C - cot∠A = 3x cotA = tanC secC - tanC = 3x 1 - sinC = 3x cosC 1 - sinC = 3x (6/7) seems like either way you go youll need to determine ab
\(c = \sqrt{7^2+6^2}\)
wait, that.... didn't go well :/
1. Use the Pythagorean theorem to find AB 2. secC = 1/cosC 3. cotA = 1/tanA 4. Use SOH CAH TOA and the identities above to find secC and cotA. 5. Set up the equation and solve for x.
lol, confusing names with convention are ya
we need the opposite, thus \(b = \sqrt{7^2-6^2}\)
hehe
ok thanks guys but can u choose the multiple choice
idk how to use the SOH CAH TOA to find secC and tanA
SOH: sin = opp/hyp CAH: cos = adj/hyp TOA: tan = opp/adj There is no cot or sec listed, but cot = 1/tan, and sec = 1/cos, so cot = adj/opp and sec = hyp/adj.
ok i understand now thanks so i narrowed it down to either being A or C im just gonna take it from here thanks alot
wlcm
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