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Is this equation correct? Solving for "r"
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\[-T(r+R)+\frac{ W }{ 2 }\cos \theta a+\frac{ W }{ 2 }\sin \theta R=0\]
\[W/2\cosθa+W/2\sinθR=Tr+TR\]
Subtract w/2cos and sin. Then divide by T and subtract R
\[\frac{ W/2\cosθa+W/2\sinθR=Tr+TR }{ T }=r\]
Ok thanks!
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