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Solve square root (2x+3) = x + 1 for x 2 +- square root 2 square root 2 4
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square both side..
\[\sqrt{2x+3}=x+1\] or \((\sqrt{2x+3})^{2}=(x+1)^{2}\)
expand right hand side
\((\sqrt{2x+3})^{2}=(x+1)^{2}\) \(2x+3 =x^2+1 + 2x\) \(2 =x^2\)
or \[x=\pm \sqrt{2}\]
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\(\pm \sqrt{2} = x \) \(x = \pm \sqrt{2} \) its easy.... not as scary as it looks lol, just we need to pen down and keep solving thats all :)
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