Question

How would the equation r = 2 - 1.5sin(delta) looks like? ( Polar equations)

Answer 1

Try converting into cartesian, by \[r = \sqrt{x ^{2}+y ^{2}}\]
and \[\sin \theta =\frac{ y }{r}\]
May be of help..

Answer 2

take a look at http://www.wolframalpha.com/input/?i=r+%3D+2-1.5sin%28theta%29

Answer 3

The graph of loser66 is good..

Answer 4

I got it. Thank you :)