Algebra
15 Online
OpenStudy (anonymous):
square root of x + 2 end root + 4 = x
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hartnn (hartnn):
like this ?
\(\sqrt{x+2}+4=x\)
then subtract 4 from both sides, what u get ?
hartnn (hartnn):
only after you have subtracted 4 from both sides, you can square both sides
and viola! square roots gets eliminated :)
OpenStudy (anonymous):
but what about the x? I have to get x by itself ! :(
OpenStudy (souvik):
do you subtract 4 from both sides...?
OpenStudy (anonymous):
yeaah so after I subtracted, I got
squareroot of x + 2 = x-4
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OpenStudy (souvik):
now square both sides..
OpenStudy (anonymous):
x + 2 = x^2 - 8x + 16 ?
OpenStudy (souvik):
get all the terms in one side and try to factor it..
OpenStudy (anonymous):
0 = x^2 - 9x +14
OpenStudy (souvik):
now factor it
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OpenStudy (anonymous):
uhmmm, how do I factor this ?
OpenStudy (souvik):
find 2 numbers which adds to -9 and multiplied to 14
OpenStudy (anonymous):
oooh waaait ! (x-7) (x-2)
OpenStudy (souvik):
well done...
now....(x-7)(x-2)=0
so (x-7)=0 and (x-2)=0
so you will get x=7 and 2
hartnn (hartnn):
there's more to this problem
it has only one solution
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OpenStudy (anonymous):
oooh why ?
hartnn (hartnn):
plug in x=7 and x=2 in your original equation
and find out by yourself :)
OpenStudy (anonymous):
oooh so the answers just x=7 ! right ?
hartnn (hartnn):
what do you get for left side when x= 2 ?
hartnn (hartnn):
correct! just x= 7 :)
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OpenStudy (anonymous):
thank you both !
hartnn (hartnn):
welcome dear :)