Question

Can anyone help to solve:

4x^2 + 17x = -4

Answer 1

I have to solve for x:

Answer 2

\[4x^{2}+17x+4=0\]
a=4, b=17, c=4, use:
\[x=\frac{ -b \pm \sqrt{(b)^{2}-4(a)(c)} }{ 2a }\]
you get x=-4 or x=-1/4

Answer 3

Thank you ghost, this the same answer that I got but I thought that I was wrong! Here is your medal!