What are the approximate solutions of 2x^2 + 5x = 4 rounded to the nearest hundredth?

No real solutions
x ≈ −6.27 and x ≈ 1.27
x ≈ −0.64 and x ≈ 3.14
x ≈ −3.14 and x ≈ 0.64

Question

What are the approximate solutions of 2x^2 + 5x = 4 rounded to the nearest hundredth?
 	
	No real solutions
	x ≈ −6.27 and x ≈ 1.27
	x ≈ −0.64 and x ≈ 3.14
	x ≈ −3.14 and x ≈ 0.64

jdoe0001 · Answer

set the equation to 0, that is $\sf \bf 2x^2+5x-4=0$ and from there use the quadratic formula to get the values for "x" => http://2.bp.blogspot.com/_9xX2yNGJA4E/TPm214sFVjI/AAAAAAAAADI/nVLP-mPhYCM/s1600/QuadraticFormula.JPG

anonymous · Answer

so c?

jdoe0001 · Answer

dunno, use the quadratic formula

jdoe0001 · Answer

plug in your values, and see what "x" is

anonymous · Answer

idk how to do that?? sorry please explain

anonymous · Answer

i got it now thank you!