Question

Can anyone help me with drafting a parabola for this equation, I need to know where to mark my graph:

y=3/2x^2

Answer 1

First thing you might mark would be the vertex. Do you have an idea of how to find the vertex?

Answer 2

The vertex is (0,0)

Answer 3

Yes :)
So then the next thing you could do is to look at a, which is 3/2.

Answer 4

Ok, then what is my next step?

Answer 5

If you had just this, y = x^2, you would first mark the vertex (0,0). Then since a = 1, you start at the vertex and go over 1 unit and up 1 unit to mark two more points (1,1) and (-1,1). In this case, a = 3/2 so you again would start at the vertex and go over 1 unit and up how many?

Answer 6

3

Answer 7

a = ?

Answer 8

a = 1 so I Mark (-1, 1)?

Answer 9

For your equation, a = 3/2 :) so (-1,3/2) and what other point?

Answer 10

Can you draw it?

Answer 11

0

Answer 12

Yes, although I'm not that good an artist :)

Answer 13

No one is worst than me at drawing even when I am right sometimes the lab does not recognize my graph