Question

solve the trigonometric equation (sinx)(2cosx+1)=0
[0,360 degrees)

Answer 1

i wouldn’t
it is easier to solve for \(x\) when it is in factored form

Answer 2

\[\sin(x)\left(2\cos(x)-1\right)=0\]
\[\sin(x)=0\] or \[2\cos(x)+1=0\iff 2\cos(x)=-1\iff \cos(x)=-\frac{1}{2}\]

Answer 3

the easy method is to solve the factors


sin(x) = 0 and 2cos(x) + 1 = 0 or cos(x) = -1/2

they will give the answers

Answer 4

Im still not 100% sure what the answer is ?

Answer 5

ok...

start with cos

what angle gives cos(x) = 1/2



here is an exact value triangle