Question

Find the center and radius of the circle with the following equation 8xsquare + 8y square + 64x-32y+32=0

Answer 1

\[8x^2+8y^2+64x-32y+32=0\] divide by 8 as step one and get
\[x^2+8x+y^2-4y+4=0\] subtract 4 and get
\[x^2+8x+y^2-4y=-4\] then "complete the square" to make it look like
\[(x-h)^2+(y-k)^2=r^2\]

Answer 2

you know how to complete the square? that is the only hardish part

Answer 3

(-4,2) 4