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Mathematics 9 Online
OpenStudy (anonymous):

If AC=25 mm and AB=15 mm, calculate the length of AD. A. 16 MM B. 15 MM C. 9 MM D. 14 MM There's a picture included

OpenStudy (anonymous):

no pic..

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

I'm doing geometry online, and I've been stuck on this question for an hour! I'm really bad with circles.

jimthompson5910 (jim_thompson5910):

use theorem 3 http://www.regentsprep.org/Regents/math/geometry/GP14/CircleSegments.htm

OpenStudy (anonymous):

I got 20....

OpenStudy (anonymous):

And 20 isn't an option :(

jimthompson5910 (jim_thompson5910):

In this case, AC*AD = AB^2

OpenStudy (anonymous):

So it would be 25 x 15=ab^2?

OpenStudy (anonymous):

I got 375=AB^2 now what do I do?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

AD is the unknown thing here

jimthompson5910 (jim_thompson5910):

AB = 15

OpenStudy (anonymous):

so it would be 25 x AD= 15?

jimthompson5910 (jim_thompson5910):

AB^2 on the right side, not just AB

OpenStudy (anonymous):

Oh okay. So I got 25 X AD= 15^2 25 X AD= 225 AD= 220 Now do I square root 220?

jimthompson5910 (jim_thompson5910):

25*AD = 225 AD = ???

OpenStudy (anonymous):

14.14?

OpenStudy (anonymous):

Or would it be just 14?

jimthompson5910 (jim_thompson5910):

think of it like this 25x = 225

OpenStudy (anonymous):

9!!!!!!! :D

jimthompson5910 (jim_thompson5910):

good

OpenStudy (anonymous):

Thank you so much!!! :D I have no Idea why I thought of square rooting.... THANK YOU!!!!!!

jimthompson5910 (jim_thompson5910):

you're welcome

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