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Trigonometry: Find the range of values of x for which 3sin2》2cos2x
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The sign there is more than and equal to..... :p
So how do you do it ? ^^'
is that 3sin2 or 3sin2x?
Its 3sin2x..sorry
in my opinion, it would be best to expand sin2x and cos2x first
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\(\large 3sin^2(x) \ge 2cos^2(x)\) ?
but if it's that, then it's different
or \(\large 3sin(2x) \ge 3cos(2x)\) ?
Yes.thr one with ... 3sin(2x)
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