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Mathematics 19 Online
OpenStudy (anonymous):

Trigonometry: Find the range of values of x for which 3sin2》2cos2x

OpenStudy (anonymous):

The sign there is more than and equal to..... :p

OpenStudy (anonymous):

So how do you do it ? ^^'

OpenStudy (anonymous):

is that 3sin2 or 3sin2x?

OpenStudy (anonymous):

Its 3sin2x..sorry

OpenStudy (anonymous):

in my opinion, it would be best to expand sin2x and cos2x first

OpenStudy (jhannybean):

\(\large 3sin^2(x) \ge 2cos^2(x)\) ?

OpenStudy (anonymous):

but if it's that, then it's different

OpenStudy (jhannybean):

or \(\large 3sin(2x) \ge 3cos(2x)\) ?

OpenStudy (anonymous):

Yes.thr one with ... 3sin(2x)

OpenStudy (primeralph):

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