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see its (-3,0) and (2,0) at axis axis, means this are the roots. (x-a)*(x-b)=0=y------- y here is zero as the graph is on s axis. where a and b are the roots. try now.
no it is. y=(x+3)*(x-2)=x^2 =x -6
sorry y=x^2+x-6
oh im sorry. see the equation of quadratic graph is Y = aX^2 +bX + c we have points (-2,0), (3,0) and (0,3) so put this into equation. you have 3=c ------(1) 0= 4a -2b + c --------(2) 0= 9a +3b + c --------(3) solving this equations will give \[Y= (-X^2/2) + (X/2) + 3\] this is according to the graph and not according to your question.
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