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p→q is false and p is true. q is ? true ?
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\[\begin{array}{|c|c|c|}\hline p&q&p\Rightarrow q\\\hline T&T&T\\T&F&F\\F&T&T\\F&F&T\\\hline\end{array}\]
sooo im right haha
\[\begin{array}{|c|c|c|}\hline p&q&p\Rightarrow q\\\hline T&T&T\\ \color{brown}T&\color{brown}F&\color{brown}F\\F&T&T\\F&F&T\\\hline\end{array}\]
I was wrong v_v
thaanks
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its ok
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