The perimeter of a rectangle is 26 feet and the length is 2 foot longer than the width. Find the dimensions an. write a system of a linear equation and solve the resulting system. let x be the length and y be the width.

first equation
2x+2y=

second equation
x+y=

what is the length ?
what is the width ?

Question

The perimeter of a rectangle is 26 feet and the length is 2 foot longer than the width. Find the dimensions an. write a system of a linear equation and solve the resulting system. let x be the length and  y be the width.


first equation
2x+2y=

second equation
x+y=

what is the length ?
what is the width ?

anonymous · Answer

2x+2y=20?
x+y=6
length 8
and width 2 ?

souvik · Answer

2x+2y=26
x-y=2

directrix · Answer

|dw:1373269114022:dw|

Also, y = x + 2

So, solve x + y = 13 and y = x + 2 simultaneously.

Post what you get and I'll tell  you what I got.

@bherre12