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algebra 2?
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(8-3 root6)(7+2root 6)
i keep getting 56-5 root6-2root 3
FOIL it out
ive been foiling and getting the wrong answer
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(8-3 root6)(7+2root 6) 56 - 21 root6 + 16 root6 - 6(root6)^2 56- 5root6 - 6*6 56-36 - 5root6 20- 5root6
Do you understand what I did???
why is the last part on the second step squared?
ohh nevermind i get it
thank you!
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\[\sqrt{6}*\sqrt{6}=\left\{ \sqrt{6} \right\}^{2}=6\]
square and squareroot are inverse operations and cancel each other out
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