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Given three segments of length x, 11-x, and x-4, respectively. Which of the following indicates the set of all numbers x such that the 3 segments could be the lengths of the sides of a triangle
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I know the answer E but why can't it be D?
A. X>4 B. X<11 C. 0<X<7 D. 5<X<15 E. 5<X<7
well, if we let 5< x < 15 so that means x = 14 is ok and our side of 11-x will give 11-14, which won't give us a valid value for the context
when i did x+11-x> x-4 it equaled 15>x then x+x-4>11-x equaled x>5 x-4=11-x>x equaled 7>x How did all of that turn out to be 5<X<7?
well, I dunno what "x" is, so not sure if I'd say that x+x-4>11-x
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I know that 11-14 won't work for the 2nd segment
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