Question

3x^2-3x^3/x^3-x simplify and state restrictions (rational variable expressions)

Answer 1

factor and cancel

Answer 2

wow that was wrong

Answer 3

\[\frac{3x^2-3x^3}{x^3-x}\]
\[=\frac{3x^2(1-x)}{x(x^2-1)}\]
\[=\frac{3x^2(1-x)}{x(x+1)(x-1)}\] there, that's better

Answer 4

then cancel an \(x\) and also \(\frac{1-x}{x-1}=-1\) making the whole thing
\[\frac{-3x}{x+1}\]