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Mathematics 8 Online
OpenStudy (anonymous):

x^2-x-20/15+2x-x^2

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

once again factor and cancel if you can

OpenStudy (anonymous):

\[x^2-x-20=(x-5)(x+4)\]

OpenStudy (anonymous):

how would i factor the denominator?

OpenStudy (anonymous):

should i rearrange the order?

OpenStudy (anonymous):

\[15+2x-x^2=(5-x)(3+x)\]

OpenStudy (anonymous):

just like the last two, you get a factor of \(-1\)

OpenStudy (anonymous):

\[\frac{(x-5)(x+4)}{(5-x)(x+3)}=-\frac{x+4}{x+3}\]

OpenStudy (anonymous):

ohh this helped a lot , thank you!

OpenStudy (anonymous):

yw

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