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y varies inversely as three times x. When x = 6, y = 4. Find x when y = 8.
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I really dont understand what it means when Y varies inversely as three times X
pretty sure it means \[y=\frac{k}{3x}\]
Y=k/3x
that is what it is.
yes but I dont know how to solve it
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to solve for \(k\) put \[4=\frac{k}{3\times 6}\]
that means \[4=\frac{k}{18}\iff k=18\times 4=72\]
what is X when Y = 8
since \[y=\frac{72}{3x}=\frac{24}{x}\] your job is to solve \[8=\frac{24}{x}\] for \(x\)
you know how to do that?
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X=3
yes
Thank You so much!
yw
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