The equation in point-slope form of the line which passes through (-2, 3) and is parallel to 3x + 2y = 10 is
..............................................

y - 3 = -3/2 (x + 2)

y - 2 = -3 (x - 3)

y - 3 = 3/2 (x - 2)

Question

The equation in point-slope form of the line which passes through (-2, 3) and is parallel to 3x + 2y = 10 is
..............................................
		
y - 3 = -3/2 (x + 2)
		
y - 2 = -3 (x - 3)
		
y - 3 = 3/2 (x - 2)

anonymous · Answer

Parallel lines have the same slope. 
So your equation would be:
y = 3/2x + b
Just plug in the x and y. (-2,3) into the equation and then solve for b.
If you need help solving it I'll do it for you.