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Mathematics 7 Online
OpenStudy (anonymous):

Which of the following is a polynomial with roots -2, -2, and 2 ? x^3 + 2x^2 + 4x + 8 x^3 + 4x^2 + 4x + 16 x^3 - 4x^2 + 4x - 16 x^3 - 2x^2 + 4x - 8

OpenStudy (anonymous):

Try substituting in the values for each polynomial, and see which one outputs zero

OpenStudy (anonymous):

Oops, the values were -2, -2i, and 2i

OpenStudy (anonymous):

if -2 is a zero (x+2) is a factor (x+2)(x+2i)(x-2i)

OpenStudy (anonymous):

Well the constant coeiffient must be the -product of all 3 roots

OpenStudy (anonymous):

its #1

OpenStudy (anonymous):

-2*-2i*2i=4i*2i=-8, the additive inverse of -8, is 8, the only polynomial with 8 as a constatnt coeiffient is #1, so it must be that 1

OpenStudy (anonymous):

The first one.

OpenStudy (anonymous):

You're right, thank you. :)

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