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vertical its right
factoring seems dificult i think its beter to use the quadractic formula
with that formula i got x=0.43 and x= 4.56
Solve the following for x:\[2 x^2-10 x+4=0 \]\[\left\{x\text{=}\frac{1}{2} \left(5-\sqrt{17}\right),x\text{=}\frac{1}{2} \left(5+\sqrt{17}\right)\right\}\]\[\{x=0.438447,x=4.56155\} \]
A plot of\[2 x^2-10 x+4 \]is attached.
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\[a x^2+b x+c=0 \]\[\left\{x=\frac{-b-\sqrt{b^2-4 a c}}{2 a},x=\frac{-b+\sqrt{b^2-4 a c}}{2 a}\right\} \]
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