Question

Solve x^2 + 8x - 48 = 0 by completing the square

Answer 1

the answer equals to (x-12)(x+4)=0 then we have x-12=0 and x+4=0,
then we have two correct answers x=12 and x=(-4).

Answer 2

so is this right ?
x2 + 8x - 48 = 0

x2 + 8x = 48

x² + 8x + ? = 48 + ?

The object is to force the left side of the equation to be a perfect square trinomial.

Take half of the coefficient of the linear x term (it is 8) --> 4 Square it. 4² = 16

x² + 8x + 16 = 48 + 16

(x + 4)^2= 64

(x + 4) = + or - radical 64

(x+4) = + or - 8

(x-12) (x+4) = 0

Answer 3

yep that's it.

Answer 4

=>X^2+8x-48=0
=>x^2+8x=48
=>x^2+8x+16=48+16
=>(x+4)^2=64
=>x+4=+-\/64
=>x=4+-8
=>x=-4+8 or x=-4-8