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Write an equation of a line in slope intercept form with slope 1/3 going through the point (-6, 2). Show your work
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slope intercept form : y = mx + b using slope 1/3 and points (-6,2) 2 = 1/3(-6) + b can you solve for b ?
no idea... v~v
y-2=1/3)*(x+6 so y=1/3)*x+4
2 = 1/3(-6) + b 2 = -2 + b 2 + 2 = b 4 = b Therefore, you equation is : y = 1/3x + 4
thankyou sooooooo much \(^~^)/
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your very welcome :)
wat about with points (2, 1) and (- 1, - 5). o.o
is this a new problem or part of the last problem ?
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