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Mathematics 16 Online
OpenStudy (anonymous):

What is the value of h in the figure below? A.12 B.16 C. 16/9 D.25/9 E.400 F.Radical-225

OpenStudy (anonymous):

OpenStudy (fifciol):

|dw:1373375585631:dw| \[b^{2}=h^2 + 16^2\] \[a^2=h^2+9^2\] \[a^2+b^2=25^2\] \[2h^2=25^2-16^2-9^2 \rightarrow h=12\] Ans. A

OpenStudy (anonymous):

thanks :)

OpenStudy (fifciol):

oh, replace a and b on the picture.

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