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In the following sequence, the 1st yerm, the 2nd term and the 3rd term are 1,2 and 3 respectively. For any positive integer n, the (n+3)th term is the sum of the (n+2)th term, the (n+1)th term and the nth term. Find the 9th term of the sequence. 1, 2, 3, 6, 11, .....
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are you sure it goes 1,2,3 6 ?
yes, the WorkSheet stated that
ok, I mis-read it.
add the last 3 numbers to get the next number
so next term = 11 + 6 + 3 = 20
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next one is 20= 3+ 6+ 11
ohh yes
and then 37?
yes
8th=68? 9th=125?
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right
oic
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