Question

Help? :(

Which value(s) of x should be excluded for the polynomial?

Answer 1

\[\frac{ x^2-16 }{ x^2-6x+9 } \]

Answer 2

the values that make the denominator 0, and thus the rational undefined

which are those?
well, set the denominator to 0 and solve for "x"
\(\bf x^2-6x+9 =0\)

Answer 3

Thanks :)