a 10g block with a charge of 8*10^-5 C is placed in an electric field E=(3000i-600j) N/C What are the magnitude and direction of the electrostatic forces on the block( relative to the positive direction of the x axis)? If the block is released from rest at the origin at time=0 what are the x and y coordinates at t=3.00 s

Question

fifciol · Answer

$$F=qE=8*10^{-5}*(3000i-600j)=0,24i-0,048j$$
$$|F|= sqrt{(0,24)^2+(0,048)^2}=0,245 N$$
$$tan theta =\frac{ -0,048 }{ 0,24 } rightarrow theta=-11,3^{o}$$
$$x= \frac{ F_{x}t^2 }{ 2m }=108$$
$$y=\frac{ F_yt^2 }{ 2m}=-21,6$$
|dw:1373532975624:dw|