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Physics 11 Online
OpenStudy (anonymous):

A uniform electric field exists in a region between two oppositely charged plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 4.0 cm away, in a time 1.7 10-8 s. (a) What is the speed of the electron as it strikes the second plate? m/s (b) What is the magnitude of the electric field ? N/C

OpenStudy (souvik):

first find acceleration of the electron...use \[d=ut+1/2at ^{2}\] here d=distance=4 cm u=initial velocity=0 m/s t=time a= acceleration... take all the variables in SI unit

OpenStudy (souvik):

then use \[v=u+at\] to find the final velocity (v)

OpenStudy (anonymous):

a=qe/m

OpenStudy (anonymous):

e is electric field , q is charge on electron , m is its mass , a is acceleration

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