The letters of the word Mississippi are placed in a hat. What is the probability that the first two letters drawn are both i if the first letter drawn is not replaced?
on the word you have 11 letters in total 4 letters are (i)
probability to draw an i would be 4/11, then probability to draw a second (i) 3/10, because now there are 10 ltrs left and 3 (i) left
There are four i's in the word and the word has 11 letters. The probability of drawing an i on the first draw is 4/11. Given that an i was drawn on the first draw, the probability of drawing an i on the second draw is 3/10. The required probability is found from the product of the 2 values of probability: \[P(2\ letter\ i)=\frac{4}{11} \times \frac{3}{10}\]
so multiply 4/11 x 3/10
6/55 ?
You answer is correct :)
thanks so much! both of you!
You're welcome :)
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