Question

Find exact value cos(pi/4) - sin(pi/6)

Answer 1

Use this!

Answer 2

I got (2-\[\sqrt{2}\])/2\[\sqrt{2}\]

Answer 3

What?

Answer 4

and its still wrong
(2-Sqrt2)/(2sqrt2)

Answer 5

Can it be simplified??

Answer 6

Using the Unit Circle we get
\[cos(\frac{\pi}{4})=\frac{\sqrt{2}}{2}\]
\[sin(\frac{\pi}{6})=\frac{1}{2}\]

Answer 7

\(\bf \cfrac{\sqrt{2}}{2}- \cfrac{\sqrt{3}}{2}\)

Answer 8

ohh shoot is sine my bad

Answer 9

\(\bf \cfrac{\sqrt{2}}{2}- \cfrac{1}{2}\)

Answer 10

i got that far

Answer 11

get the lcd, add the rationals, all you can simplify really

Answer 12

So from that we are given,
\[\frac{\sqrt{2}}{2}-\frac{1}{2}\]=\[\frac{\sqrt{2}-1}{2}\]

Answer 13

One word Awesome!!!