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Mathematics 15 Online
OpenStudy (anonymous):

(4+i)/(3-2i)

hartnn (hartnn):

have any ideas how to start ?

OpenStudy (anonymous):

\[ \frac{ (4 +i) }{ (3-2i) }\]

OpenStudy (anonymous):

.769+.846i

OpenStudy (jdoe0001):

use the conjugate luke

OpenStudy (jdoe0001):

\(\bf \cfrac{ (4 +i) }{ (3-2i) } \times \cfrac{(3+2i)}{(3+2i)}\)

OpenStudy (anonymous):

I got\[\frac{ 10+11i }{ 13}\]

OpenStudy (jdoe0001):

that's the simplified form of it :)

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