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(4+i)/(3-2i)
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have any ideas how to start ?
\[ \frac{ (4 +i) }{ (3-2i) }\]
.769+.846i
use the conjugate luke
\(\bf \cfrac{ (4 +i) }{ (3-2i) } \times \cfrac{(3+2i)}{(3+2i)}\)
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I got\[\frac{ 10+11i }{ 13}\]
that's the simplified form of it :)
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