Question

How do you find the sixth term of a geometric sequence with t5 = 24 and t8 = 3.

Answer 1

t5 = a*r^4 = 24
t8 = a.r^7 = 3
Dividing one by the other
r^3 = 1/8
r = 1/2
t6 = a.r^5 = t5*r = 24 * 1/2 = 12

Answer 2

@heather040200 thank youu :D

Answer 3

no problem :)