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Mathematics 8 Online
OpenStudy (anonymous):

Which of the following fractions, if any, is(are) in simplest form?(i) 9/1485(ii) 21/101(iii) 42/43 A) A) (i) and (ii) only B) B) (i) and (iii) only C) C) (ii) and (iii) only D) D) None of the other choices.

OpenStudy (anonymous):

simplest form means they cannot be reduced anymore if numerator or denominator is a prime number, you can say that fraction is in simplest form

OpenStudy (anonymous):

for this assignment this will be enough, because two of three fractions have prime numbers in their denominator

OpenStudy (anonymous):

so then the answer is d, correct?

OpenStudy (anonymous):

prime numbers are numbers that can only be divided with one and themselves here is a list of a first few: http://www.whatareprimenumbers.com/media/uploads/images/67/list-of-prime-numbers.jpg

OpenStudy (anonymous):

nop, two of the given fractions are indeed in the simplest form

OpenStudy (anonymous):

find which two have prime number in their denominator

OpenStudy (anonymous):

Oh ok

OpenStudy (anonymous):

let me help you. \[\frac{ 21 }{ 101 }\] 101 is a prime number (it can be divided only with 1 and 101). hence, 21/101 is in it's simplest form

OpenStudy (anonymous):

Ok so then it is C

OpenStudy (anonymous):

yes it is:) gj

OpenStudy (anonymous):

Thanks for your help!

OpenStudy (anonymous):

np;)

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