Which of the following fractions, if any, is(are) in simplest form?(i) 9/1485(ii) 21/101(iii) 42/43 A) A) (i) and (ii) only B) B) (i) and (iii) only C) C) (ii) and (iii) only D) D) None of the other choices.
simplest form means they cannot be reduced anymore if numerator or denominator is a prime number, you can say that fraction is in simplest form
for this assignment this will be enough, because two of three fractions have prime numbers in their denominator
so then the answer is d, correct?
prime numbers are numbers that can only be divided with one and themselves here is a list of a first few: http://www.whatareprimenumbers.com/media/uploads/images/67/list-of-prime-numbers.jpg
nop, two of the given fractions are indeed in the simplest form
find which two have prime number in their denominator
Oh ok
let me help you. \[\frac{ 21 }{ 101 }\] 101 is a prime number (it can be divided only with 1 and 101). hence, 21/101 is in it's simplest form
Ok so then it is C
yes it is:) gj
Thanks for your help!
np;)
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