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ok i need help subtracting x+2 over x squared +4x+3 minus x+1 over x+3
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\[\frac{x+2}{x^2+4x+3}-\frac{x+1}{x+3}\]?
yes
factor the bottom of the fraction on the left and tell me what you have
factor x^2+4x+3
(x-4((x+1)
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x^2+4x+3=0?
can you solve this?
no
well you need to go back and learn how to solve quadratic equations \[\frac{x+2}{(x+3)(x+1)}-\frac{x+1}{x+3}\] so we need to find a common denom and that will be (x+3)(x+1) so we need to multiply the rhs by (x+1)(x+1) \[\frac{x+2}{(x+3)(x+1)}-\frac{(x+1)(x+1)}{(x+3)(x+1)}\]= \[\frac{x+2}{(x+3)(x+1)}-\frac{x^2+2x+1}{(x+3)(x+1)}\]= \[\frac{x+2-x^2-2x-1}{(x+3)(x+1)}\]= \[\frac{-x^2-x+1}{(x+3)(x+1)}\]
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