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Calculus1 14 Online
OpenStudy (anonymous):

Find the derivatives y' . Use the rules y= (square root x)(1+x^2) y= (1/Squareroot x + squareroot x)^2

OpenStudy (anonymous):

use product rule. |dw:1373420802360:dw|

OpenStudy (anonymous):

where u=sqrt(x) v=1+x^2

OpenStudy (anonymous):

how do you do u'

OpenStudy (anonymous):

that is just the derivative of u

OpenStudy (anonymous):

so 1/2 x ^ -1/2

OpenStudy (anonymous):

|dw:1373420964897:dw|

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