A vending machine's coin box contains nickels, dimes, and quarters. The total number of coins in the box is 336. The number of dimes is three time the number of nickels and quarters together. If the box contains 33 dollars and 20 cents, find the number of nickels, dimes, and quarters that it contains.

Question

mertsj · Answer

Let n = the number of nickels
Let d = the number of dimes
Let q = the number of quarters
What is n+d+q  ?

anonymous · Answer

n+d+q = 336
3(n+q) = d

mertsj · Answer

n nickels are worth 5n cents or .05n dollars
d dimes are worth 10d cents or .10d dollars
q quarters are worth 25q cents or .25 dollars

mertsj · Answer

Can you write the third equation now?

anonymous · Answer

.05n + .10d + .25q = 33.20     This is where i get stuck

mertsj · Answer

I would make my life easier and multiply by 100 to get
5n+10d+25q=3320

mertsj · Answer

Then I would divide by 5 to get
n + 2d+5q=664

mertsj · Answer

Does that help?

anonymous · Answer

not really i am using substitution method be not getting any where (n + 2d+5q=664 +( -1)n+d+q = 336) = d+4q=328 ???

mertsj · Answer

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