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Mathematics 10 Online
OpenStudy (anonymous):

http://tinypic.com/r/2dkz987/5 Write the standard equation of the circle below answers : (x - 1)2 + (y + 2)2 = 9 (x + 1)2 + (y - 2)2 = 3 (x - 1)2 + (y + 2)2 = 3 (x + 2)2 + (y - 1)2 = 9

OpenStudy (anonymous):

i think its the second one.. not sure

OpenStudy (anonymous):

Equation of a circle \[(x-h)^2+(y-k)^2=r^2\]

OpenStudy (anonymous):

(h,k) is the center (red dot) of your circle r=radius

OpenStudy (anonymous):

so i dont get the radius?

OpenStudy (anonymous):

h is 1 and k is -2 right

OpenStudy (anonymous):

yeah, to get r just count horizontsally from the red dot to the outside of the circle

OpenStudy (anonymous):

so itd be 6 then ? >.<

OpenStudy (anonymous):

\[(x-1)^2+(y-(-2))^2=(x-1)^2+(y+2)^2\] and no it'd be 3

OpenStudy (anonymous):

yeah i got it lol do you multipy the 3 ?

OpenStudy (anonymous):

ijs we already have this much and we know its a number squareed (9) so you could just choose the answer there

OpenStudy (anonymous):

and yeah its 3 squared=9

OpenStudy (anonymous):

so itd be the first one ??

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

yaaay thanks ! (:

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