Question

Engineers have designed a tunnel with the equation below, measured in feet. A design for a larger tunnel needs to be twice as wide and 3 times as tall. Find the dimensions for the larger tunnel.

x^2/64 +y^2/36 = 1

a) width: 18 ft; height: 16 ft.
b) width: 32 ft; height: 18 ft.
c) width: 16 ft; height: 18 ft.
d) width: 18 ft; height: 32 ft.

Answer 1

What work have you so far?

Answer 2

i dont understand how to start

Answer 3

@dumbsearch2

Answer 4

Hint: Solve x for Y equal to zero ...to start