Question

Does this make sense?

Answer 1

Work = Fd,

The work done on two charges/dipoles(Repulsive force).
A charge A and B are placed near each other like so:


There is a repulsive force between them of X.
The work done over a displacement "d" = Xd :

So, work is done on both charges A and B because the repulsive force was applied, but what if A was fixed? Hence F = X and d = 0?
Work is only done on B?



Is work still the same on B or increased?
w for A is = to zero?